#include <iostream>
using namespace std;
int main()
{
int a[13],b[12],n,m,i,j,sum,x;
for(m=1;;m++)
{
cin>>n;
if(n<0)
{
break;
}
a[0]=n;
for(i=1;i<13;i++)
{
cin>>a[i];
}
for(i=0;i<12;i++)
{
cin>>b[i];
}
cout<<"Case "<<m<<":"<<endl;
sum=0;
for(i=0;i<12;i++)
{
if(a[i]>=b[i])
{
cout<<"No problem! :D"<<endl;
x=a[i]-b[i];
sum=sum+x;
}
else if(a[i]<b[i])
{
sum=sum+a[i];
if(sum>=b[i])
{
sum=sum-b[i];
cout<<"No problem! :D"<<endl;
}
else
{
cout<<"No problem. :("<<endl;
}
}
}
}
return 0;
}
Category UVa
UVa – 11587 – Brick Game
#include <stdio.h>
#include <stdlib.h>
int main()
{
int T,i,j,N,c,d;
scanf("%d",&T);
for(i=1;i<=T;i++)
{
scanf("%d",&N);
int A[N];
for(j=0;j<N;j++)
{
scanf("%d",&A[j]);
}
c=0;
d=0;
for(j=0;j<N-1;j++)
{
if(A[j]<A[j+1])
{
c++;
}
else if(A[j]>A[j+1])
{
d++;
}
}
if(c==N-1 || d==N-1)
{
printf("Case %d: %d\n",i,A[N/2]);
}
}
return 0;
}
UVa – 10487 – Closest Sums
#include <iostream>
using namespace std;
int main()
{
long long int n,q,i,j,k,m,d,p,x,f,c,h;
for(m=1;;m++)
{
cin>>n;
if(n==0)
{
break;
}
long long int a[n];
for(i=0;i<n;i++)
{
cin>>a[i];
}
cin>>q;
cout<<"Case "<<m<<":"<<endl;
for(k=0;k<q;k++)
{
cin>>x;
d=10000000000;
c=0;
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
p=a[i]+a[j];
if(p==x)
{
h=p;
c=1;
break;
}
else if(p>x)
{
f=p-x;
if(f<d)
{
d=f;
h=p;
}
}
else if(p<x)
{
f=x-p;
if(f<d)
{
d=f;
h=p;
}
}
}
if(c==1)
{
break;
}
}
cout<<"Closest sum to "<<x<<" is "<<h<<"."<<endl;
}
}
return 0;
}
UVa – 10370 – Above Average
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i,j,s,T;
double sum,p,avrg,d,c;
scanf("%d",&T);
for(j=0;j<T;j++)
{
scanf("%d",&s);
int A[s];
for(i=0;i<s;i++)
{
scanf("%d",&A[i]);
}
sum=0;
for(i=0;i<s;i++)
{
sum=sum+A[i];
}
d=s;
avrg=(sum*1.0/d*1.0);
c=0;
for(i=0;i<s;i++)
{
if(A[i]>avrg)
{
c++;
}
}
p=(c*1.0/s*1.0)*100;
printf("%.3lf%%\n",p);
}
return 0;
}
UVa – 10300 – Ecological Premium
#include <iostream>
using namespace std;
int main()
{
long long int t,m,n,i,j,sum;
cin>>t;
for(i=0;i<t;i++)
{
cin>>n;
m=n*3;
long long int A[m];
for(j=0;j<m;j++)
{
cin>>A[j];
}
sum=0;
for(j=0;j<m-2;)
{
sum=sum+(A[j]*A[j+2]);
j=j+3;
}
cout<<sum<<endl;
}
return 0;
}