In this problem, since there is no mention of limit of input in a particular test case, so we have assumed the empty string to be the termination. That’s why we have used getline() for taking input instead of cin. Otherwise there is no way of returning to another test case taking only string by cin.
#include <bits/stdc++.h>
#define ms(a,b) memset(a,b,sizeof(a))
#define pb(a) push_back(a)
#define db double
#define ft float
#define ll long long
#define ull unsigned long long
#define ff first
#define ss second
#define sz(x) x.size()
#define qu queue
#define pqu priority_queue
#define vc vector
#define vi vector<int>
#define vll vector<long long>
#define pii pair<int,int>
#define pis pair<int,string>
#define psi pair<string,int>
#define all(x) x.begin(),x.end()
#define CIN ios_base::sync_with_stdio(0); cin.tie(0)
#define loop0(i,n) for(int i=0;i<n;i++)
#define loop1(i,n) for(int i=1;i<=n;i++)
#define stlloop(x) for(__typeof(x.begin()) it=x.begin();it!=x.end();it++)
#define gcd(a, b) __gcd(a, b)
#define lcm(a, b) ((a)*((b)/gcd(a,b)))
#define case(z,x) cout<<"Case "<<i<<": "<<x<<endl
#define case(z) cout<<"Case "<<z<<": "
#define PI 3.14159265358979323846264338328
#define valid(tx,ty) tx>=0 && tx<r && ty>=0 && ty<c
#define MAX 2000
/*----------------------Graph Moves----------------*/
//const int fx[]={+1,-1,+0,+0};
//const int fy[]={+0,+0,+1,-1};
//const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1}; // Kings Move
//const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1}; // Kings Move
//const int fx[]={-2, -2, -1, -1, 1, 1, 2, 2}; // Knights Move
//const int fy[]={-1, 1, -2, 2, -2, 2, -1, 1}; // Knights Move
/*------------------------------------------------*/
using namespace std;
map<string,vector<string>> mp;
bool check(string a, string b)
{
int cnt=0;
if(sz(a)!=sz(b)) return 0;
else
{
loop0(i,sz(a))
{
if(a[i]!=b[i]) cnt++;
if(cnt>1) return 0;
}
}
return cnt==1;
}
int bfs(string src, string dst)
{
map<string,int>dis;
map<string,bool>visited;
queue<string>Q;
Q.push(src);
dis[src]=0;
visited[src]=1;
while(!Q.empty())
{
string u=Q.front();
Q.pop();
if(u==dst) return dis[u];
loop0(i,sz(mp[u]))
{
string v=mp[u][i];
if(!visited[v])
{
dis[v]=dis[u]+1;
visited[v]=1;
Q.push(v);
}
}
}
}
int main()
{
// CIN;
// freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
int t;
cin>>t;
for(int z=1; z<=t; z++)
{
string str;
vector<string>v;
while(cin>>str && str!="*") v.pb(str);
loop0(i,sz(v))
{
for(int j=i+1; j<sz(v); j++)
if(check(v[i],v[j]))
{
mp[v[i]].pb(v[j]);
mp[v[j]].pb(v[i]);
}
}
getchar();
string s1;
while(1)
{
getline(cin,s1);
if(s1=="") break;
bool x=0;
string s3,s4;
loop0(i,sz(s1))
{
if(s1[i]==' ')
{
x=1;
continue;
}
if(!x)
s3+=s1[i];
else
s4+=s1[i];
}
cout<<s3<<" "<<s4<<" "<<bfs(s3,s4)<<endl;
}
if(z!=t) cout<<endl;
mp.clear();
}
return 0;
}